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4n^2+40n+84=0
a = 4; b = 40; c = +84;
Δ = b2-4ac
Δ = 402-4·4·84
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-16}{2*4}=\frac{-56}{8} =-7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+16}{2*4}=\frac{-24}{8} =-3 $
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